Dobrý deň chcela by som skontrolovať túto úlohu či mám dobré spravenú, lebo som sa už v tom stratila.
Vzorce na trojboký hranol
Objem V = Sp . v
Povrch S = 2 . Sp + Spl
1.Podstava kolmého trojbokého hranola je pravouhlý trojuholník, ktorého prepona je 10 cm a jeho odvesna 60 mm. Výška hranola je 9 cm. Vypočítajte objem a povrch hranola.
a = 6 cm 60 mm = 6 cm
b = ? cm
c = 10 cm
v = 9 cm
a2+b2=c2
62 + b2 = 102
36 + b2 = 10 . 10
36 + b2 = 100 / - 36
b2 = 100 – 36
b2 = 64
b2 = √64
b = 8 cm
S = 2 . Sp + Spl
Sp = a . va /2
Sp = 8*6 / 2
Sp = 48 / 2
Sp = 24 cm 2
24.9 = 216 cm 3
S = 2 . S + 10 + 6 + 8 . 9
S = 2 . 216 + 10 + 6 + 8 . 9
S = 432 + 24 . 9
S = 456 . 9
S =4104 cm2
V=Sp.v
V= 216 . 9
V= 1944 cm 3
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